Scala，Play，Akka，Websocket:如何通过websocket传递actor消息 [英] Scala, Play, Akka, Websocket: how to pass actor messages through websocket

问题描述

我有一个随应用程序一起启动的actor，它在后台运行以监视某些更改以及是否有任何报告.目前，它只是控制台的println.我需要做的是每当有新消息时-使用Websocket将其发送到前端.

I have an actor which is launched with application, running in the background watching for certain changes and if there are any reporting them. At the moment it just a println to the console. What I need to do is whenever there is a new message - send it to the front end using Websocket.

这是我的Play Global对象，在其中启动了监视/侦听演员:

This is my Play Global object where the monitoring/listening actor is launched:

object Global extends GlobalSettings {

    override def onStart(app: Application) {

        class Listener extends Actor {
            //This needs to be changed to pass messages to Websocket, how?
            def receive = {
                case Create(path) => println("CREATE " + path)
                case Delete(path) => println("DELETE " + path)
                case Modify(path) => println("MODIFY " + path)
            }
        }

        val listener = Akka.system.actorOf(Props[Listener], "listener")
        val swatch = Akka.system.actorOf(Props[SwatchActor], "swatch")
        swatch ! Watch("/folder/path", Seq(Create, Modify, Delete), true, Some(listener))

    }

}

这是我的Play控制器:

This is my Play controller:

object Application extends Controller {

    def test = WebSocket.using[String] { request =>

        //This hopefully gets the listener actor reference?
        val listener = Akka.system.actorSelection("/user/listener")

        val (out, channel) = Concurrent.broadcast[String]
        val in = Iteratee.foreach[String] { msg =>
            //Actor messages must be pushed here, how?
            channel push("RESPONSE: " + msg)
        }

        (in, out)

    }   

}

我了解到，要建立Websocket连接，必须有一个初始的输入".

I understand that in order for websocket connection to be established there has to be an initial "in".

所以我的问题是:

1. 如何修改Listener actor以将消息推送到Websocket?
2. 建立websocket连接后，我需要做些什么来准备actor推送消息?
3. 如何将消息从侦听器参与者推送到网络套接字?

1. How do I modify the Listener actor to push messages to Websocket?
2. What do I need to do to prepare the actor to push messages once the websocket connection is established?
3. How do I push messages from the listener actor to the websocket?

推荐答案

我找到了解决方案.

必须从单独的文件中导入的案例类:

Case class that has to be imported from a separate file:

case class Start(out: Concurrent.Channel[String])

全局对象:

object Global extends GlobalSettings {

    override def onStart(app: Application) {

        class Listener extends Actor {
            var out = {
                val (enum, chan) = Concurrent.broadcast[String]
                chan
            }
            def receive = {
                //Websocket channel out is set here
                case Start(out) => this.out = out
                //Pushing messages to Websocket
                case Create(path) => this.out.push(path.toString)
                case Delete(path) => this.out.push(path.toString)
                case Modify(path) => this.out.push(path.toString)
            }
        }

        val listener = Akka.system.actorOf(Props[Listener], "listener")
        val swatch = Akka.system.actorOf(Props[SwatchActor], "swatch")
        swatch ! Watch("/folder/path", Seq(Create, Modify, Delete), true, Option(listener))

    }

}

播放控制器:

object Application extends Controller {

    def test = WebSocket.using[String] { request =>

        val (out, channel) = Concurrent.broadcast[String]

        val listener = Akka.system.actorSelection("akka://application/user/listener")
        //This is where the websocket out channel is being passed to the listener actor
        listener ! Start(channel)

        val in = Iteratee.foreach[String] { msg =>
            channel push("RESPONSE: " + msg)
        }

        (in, out)

    }   

}

这篇关于Scala，Play，Akka，Websocket:如何通过websocket传递actor消息的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！