在Scala中的play WebSocket中调用方法 [英] Calling a method in play WebSocket in Scala

问题描述

我是scala，Play框架和Akka的新手.我的功能定义为

I am new to scala, Play framework and Akka. I have function defined as

def socket = WebSocket.accept[String, String] { request =>
    ActorFlow.actorRef(out => MyWebSocketActor.props(out))
  }

我想从其他类中调用它.我不清楚如何调用此函数，因为我不能通过

This i want to call from other class .I am not clear how to call this function as, i can't call this by

objectName.socket(implict req:RequestHeader)

我正在Play 2.5.3，Scala 2.11.7和Akka 2.4.7中工作.

I am working in Play 2.5.3 , Scala 2.11.7 and Akka 2.4.7 .

它给我错误:'=>' expected, ')' found

推荐答案

我仍然不确定这样做的好处是什么，但我会尽力回答您的问题.

I'm still not sure, what the benefit of that would be, but I'll try to answer your question.

首先，这种(objectName.socket(implict req:RequestHeader))并不是您如何调用带有隐式参数的方法(在隐式参数中也有错字).

First of all, this (objectName.socket(implict req:RequestHeader)) ist not how you call a method with an implicit parameter (also you have a typo there in implicit).

但是正如您已经正确指出的那样，您需要一个隐式的RequestHeader，因此您只能在Controller的上下文中调用此方法.

But as you already pointed out correctly, you need an implicit RequestHeader, so you only can call this method within the context of a Controller.

def anotherControllerAction = objectName.socket

def anotherControllerAction = objectName.socket

那基本上只是将anotherControllerAction指向套接字实现.然后，您仍然需要将anotherControllerAction放入路由文件中.

That would basically just point anotherControllerAction to the socket implementation. Then you still need to put anotherControllerAction into your routes file.

您可能想更详细地描述您实际想要实现的目标

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