Scala使多个选项检查更加简洁 [英] Scala make multiple option checks more concise

问题描述

在Scala和Play框架中使用选项，是否有更简洁的方法来检查x数量的变量?

Working with Options in Scala and Play Framework, is there a more concise way of checking x amount of variables like so?

if (a.isDefined || b.isDefined || c.isDefined || d.isDefined ...) {

}

有可能像(a,b,c,d).isDefined这样的班轮吗?

Is a one liner something like (a,b,c,d).isDefined possible?

谢谢

推荐答案

在我的头顶上，也许有一个更好的方法:

On top of my head, probably there's a nicer way:

List(a, b, c, d).exists(_.isDefined)

对于and(来自Rob Starling的评论):

For ands (from Rob Starling comment):

List(a, b, c, d).forall(_.isDefined)

您还可能具有更复杂的条件组成:

You could also have more complex condition compositions:

// (a || b) && (c || d)
List(
  List(a, b).exists(_.isDefined), 
  List(c, d).exists(_.isDefined)
).forall(identity)

// (a && b) || (c && d)
List(
  List(a, b).forall(_.isDefined), 
  List(c, d).forall(_.isDefined)
).exists(identity)

以此类推.

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