在Play Framework 2.0模板中使用选项帮助器 [英] Use of option helper in Play Framework 2.0 templates

问题描述

我正在尝试使用views.html.helper.select(文档此处).我不知道scala，所以我正在使用java.我需要将Seq [(String)(String)]类型的对象传递给模板，对吗?像这样:

I'm trying to use views.html.helper.select (documentation here). I don't know scala, so i'm using java. I need to pass object of type Seq[(String)(String)] to the template right? Something like:

@(fooForm:Form[Foo])(optionValues:Seq[(String)(String)])

@import helper._

@form(routes.foo){
  @select(field=myForm("selectField"),options=optionValues)
}

我不知道如何在Java中创建Seq [(String)(String)].我需要用我的枚举类中的对(id，title)填充此集合.

I don't know how to create Seq[(String)(String)] in java. I need to fill this collection with pairs (id,title) from my enum class.

有人可以给我一些例子来说明如何使用选择助手吗?

Can somebody show me some expample how to use the select helper?

我在用户上发现了此线程组，但是凯文(Kevin)的回答对我没有多大帮助.

I found this thread on users group, but Kevin's answer didn't helped me a lot.

推荐答案

正确的类型是:Seq[(String, String)].它表示成对的String序列.在Scala中，有一种使用箭头定义对的方法:a->b == (a, b).因此，您可以编写例如:

The right type is: Seq[(String, String)]. It means a sequence of pairs of String. In Scala there is a way to define pairs using the arrow: a->b == (a, b). So you could write e.g.:

@select(field = myForm("selectField"), options = Seq("foo"->"Foo", "bar"->"Bar"))

但是，如文档中所示，还有另一个助手来构建选择选项的序列:options，因此您可以将上面的代码重写为:

But there is another helper, as shown in the documentation, to build the sequence of select options: options, so you can rewrite the above code as:

@select(myForm("selectField"), options("foo"->"Foo", "bar"->"Bar"))

在您的选项值与其标签相同的情况下，您甚至可以将代码缩短为:

In the case your options values are the same as their label, you can even shorten the code to:

@select(myForm("selectField"), options(List("Foo", "Bar")))

(注意:在Play 2.0.4中，options(List("Foo", "Bar"))无法编译，因此您可以尝试使用此options(Seq("Foo", "Bar")))

(note: in Play 2.0.4 options(List("Foo", "Bar")) doesn't compile, so you can try this options(Seq("Foo", "Bar")))

要填充Java代码中的选项，更方便的方法是使用重载的

To fill the options from Java code, the more convenient way is to use either the overloaded options function taking a java.util.List<String> as parameter (in this cases options values will be the same as their label) or the overloaded function taking a java.util.Map<String, String>.

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