PLSQL按问题排序 [英] PLSQL order by issue

问题描述

我对以下SELECT有一个有趣的问题.

I have an interesting issue with the below SELECT.

关于ORDER BY子句；我正在尝试使用名为"p_sortby"的变量进行排序.

Its about ORDER BY clause; I am trying to sort using a variable called "p_sortby".

Order by可以按列名或列位置(1、2，...等)使用.
不知何故，如果我在PL/SQL中使用头寸，那将不起作用. 因此，我必须使用列名，我们不能简单地在其中传递varchar2字符串， 我们需要使用真实的列名.我注意到，它仅适用于varchar2类型的列. 例如，它不适用于数字列.

Order by can be used by column name or column position, (1, 2, … etc. ).
Somehow, if I use position in the PL/SQL, it doesn’t work. So I have to use column name which we can’t simply passing a varchar2 string there, we need to use real column name. I noticed that it only applies to varchar2 type column though. It doesn’t apply to for instance, a number column.

请大家就此类问题向我提出建议，以解决该问题.

Can you all please advise me on this kind of issue about how to solve.

/*I am sorry as I cannot paste the format correct here*/.

请大家编辑SELECT并输入所需的格式.

Could you all please edit the SELECT and put the required format.

select distinct gl.group_id, gl.group_name
     from test_group gl
    where gl.group_org_id = p_orgid
      and (   gl.group_name_key like '%' || p_name || '%' 
              or p_name is null
              or p_name = ''
          )
      and (   gl.group_description_key like '%' || p_description || '%' 
              or p_description is null
              or p_description = ''
          )
      and (   gl.status_code = p_statuscode
              or p_statuscode is null
              or p_statuscode = 99
          )
      and gl.group_id in (
                  select gm.group_id
                      from test_group_member gm join test_org_person op
                                on gm.person_id = op.o_person_id
                           join test_person pp
                                on op.o_person_id = pp.person_id
                      where (   upper(pp.firstname) like
                                 '%' || upper(p_adminfirstname) || '%'
                                or p_adminfirstname is null
                                or p_adminfirstname = ''
                            )
                        and (   upper(pp.lastname) like
                                '%' || upper(p_adminlastname) || '%'
                                or p_adminlastname is null
                                or p_adminlastname = ''
                            )
                        and (   upper(op.emplid) like
                                '%' || upper(p_adminemployeeid) || '%'
                                or p_adminemployeeid is null
                                or p_adminemployeeid = ''
                            )
                        and gm.isadmin = 1)
     and gl.group_id in (
              select gm.group_id
                  from test_group_member gm join test_org_person op
                           on gm.person_id = op.o_person_id
                       join test_person pp
                           on op.o_person_id = pp.person_id
                  where (   upper(pp.firstname) like
                            '%' || upper(p_memberfirstname) || '%'
                            or p_memberfirstname is null
                            or p_memberfirstname = ''
                        )
                    and (   upper(pp.lastname) like
                            '%' || upper(p_memberlastname) || '%'
                            or p_memberlastname is null
                            or p_memberlastname = ''
                        )
                    and (   upper(op.emplid) like
                            '%' || upper(p_memberemployeeid) || '%'
                            or p_memberemployeeid is null
                            or p_memberemployeeid = ''
                        )
                    and gm.isadmin = 0) 

推荐答案

尝试使用DECODE()函数将ORDER BY子句选择为单独的列:

Try to select the ORDER BY clause as a separate column using the DECODE() function:

SELECT DECODE(p_sortby, 'ID', gl.group_id, 'NAME', group_name) AS sort, ...
...
ORDER BY 1

我不确定您所说的无效"是什么意思.如果您表示member_count未按预期排序，请使用TO_CHAR(gl.member_count，'000000')强制执行格式化的字符串转换. (将格式掩码调整为预期的位数)

I'm not sure what you mean by "doesn't work". If you mean that member_count is not sorted as you expect, use TO_CHAR(gl.member_count, '000000') to enforce a formatted string conversion. (adjust format mask to expected number of digits)

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