如何从Oracle/PLSQL中的零件创建日期时间? [英] How to create a datetime from parts in Oracle/PLSQL?

问题描述

我有一个约会(4/30/2012)，一个小时(4)和一分钟(45).我需要将其转换为Oracle日期时间值，以便在PLSQL/Oracle SELECT语句中进行比较.理想情况下，会有一个像这样的函数(C#，因为我知道的更好一些):

I have a date (4/30/2012), an hour (4) and a minute (45). I need to convert that to an Oracle datetime value for comparison in a PLSQL/Oracle SELECT statement. Ideally, there would be a function like this (C# since I know it a little better):

var date = "4/30/2012";
var hour = "4";
var minute = "45";
DateTime myDateTime = convertDateTime(date, hour, minute);

我有一个包含三列的表格来组成事件的日期和时间.我有另一个表，其中包含根据其开始日期和结束日期可能不匹配的项目.在伪SQL中，这是我想要做的事情:

I have a table with three columns to make up the date and time of an event. I have another table that has items that may or may not match based on their start and end dates. In pseudo SQL, here's what I'm trying to do:

SELECT 
    G.Name, 
    (SELECT MAX(Cost) 
        FROM CrappyTable AS C 
        WHERE G.StartTime < convertDateTime(C.Date, C.Hour, C.Minute) 
        AND G.EndTime > convertDateTime(C.Date, C.Hour, C.Minute)) as Cost
FROM GoodTable as G
WHERE G.Price < 100.00;

或选择名称和最高费用(从某个时间范围内的报告费用中选择) 价格低于$ 100的地方."

OR "Select name and max cost (from reported cost during a time range) where the price is less than $100."

是否存在一个可能执行上述convertDateTime函数之类的功能?

Is there an existing function that might do something like the above convertDateTime function?

推荐答案

连接您的日期和时间字段，并将其传递给TO_DATE(假设24小时制):

Concatenate your date and time fields and pass them to TO_DATE (assumes 24 hour clock time):

TO_DATE(date||' '||hour||':'||minute,'MM/DD/YYYY HH24:MI')

这会将您的日期/时间值转换为Oracle DATE类型.

This will convert your date/time values to an Oracle DATE type.

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