char *字符串文字如何有效? [英] how is char * to string literal valid?

问题描述

因此，根据我的理解，指针变量指向一个地址.那么，以下代码在C ++中如何有效?

So from my understanding pointer variables point to an address. So, how is the following code valid in C++?

char* b= "abcd"; //valid
int *c= 1; //invalid

推荐答案

在C和非常老版本的C ++中，字符串文字"abcd"的类型为char[]，即字符数组.这样的数组自然可以由char*指向，但不能由int*指向，因为这不是兼容类型.

In C and very old versions of C++, a string literal "abcd" is of type char[], a character array. Such an array can naturally get pointed at by a char*, but not by a int* since that's not a compatible type.

但是，C和C ++是不同的，通常是不兼容的编程语言.大约20年前，他们彼此失去了兼容性.

However, C and C++ are different, often incompatible programming languages. They dropped compatibility with each other some 20 years ago.

在标准C ++中，字符串文字的类型为const char[]，因此，您发布的任何代码在C ++中均无效.这不会编译:

In standard C++, a string literal is of type const char[] and therefore none of your posted code is valid in C++. This won't compile:

char* b = "abcd";        //invalid, discards const qualifier

这将:

const char* c = "abcd";  // valid

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