将二维数组作为参数传递 [英] Passing 2-D array as argument

问题描述

我正在尝试将二维数组传递给一个接受指向指针的指针的函数.而且我了解到，二维数组并不是指向指针的指针(指向一维数组的指针).我在编译以下代码时遇到此错误.

I am trying to pass a 2-d array to a function which accept a pointer to pointer. And I have learnt that a 2-d array is nothing a pointer to pointer(pointer to 1-D array). I when I compile the below code I got this error.

#include<iostream>

void myFuntion(int **array)
{
}
int main()
{
   int array[][]= {{1,2,3,4},{5,6,7,8,9},{10,11,12,13}};
   myFuntion(array);
   return 0;
}

在函数'int main()'中: 第5行:错误:将数组"声明为多维数组时，除第一个数组外，所有维都必须具有边界 编译由于-Wfatal-errors而终止.

In function 'int main()': Line 5: error: declaration of 'array' as multidimensional array must have bounds for all dimensions except the first compilation terminated due to -Wfatal-errors.

如果可能的话，有人可以消除我对此和某些文档的怀疑.

Can anybody clear my doubt regarding this and some docs if possible for my more doubts.

推荐答案

  void myFunction(int arr[][4])

您可以在第一个[]中放置任何数字，但编译器将忽略它.在将向量作为参数传递时，必须指定除第一个尺寸以外的所有尺寸.

you can put any number in the first [] but the compiler will ignore it. When passing a vector as parameter you must specify all dimensions but the first one.

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