p =数组是否与p =& array [0]相同? [英] Is p = array the same as p = &array[0]?

问题描述

int numbers[20];
int * p;    

下面的两个作业是否相同?

Are the two assignments below the same?

p = numbers;
p = &numbers[0];

推荐答案

是的.

在这种情况下，数组的名称衰减为指向其第一个元素的指针.

In this case, Name of the array decays to a pointer to its first element.

因此

p = numbers;       //Name of the array

与:

p = &numbers[0];   //Address of the First Element of the Array

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