如何使指针指向2D数组的任何数组元素? [英] How to make a pointer point to any array element of a 2D array?

问题描述

直指重点，

我希望字符指针p指向唯一包含字符'T'的数组元素.

I want the character pointer p to point to the only array element that contains the character 'T'.

char a[100][100];
char *p;

for(int i=0;i<4;i++)
  for(int j=0;j<4;j++)
    if(a[i][j] == 'T')
      p = a[i][j];

P.S.我尝试使用*，**等的各种组合，但是似乎没有任何效果.

P.S. I tried with various combinations of *, **, etc but nothing seems to work.

推荐答案

使用其地址:

char a[100][100];
char *p;

for(int i=0;i<4;i++)
  for(int j=0;j<4;j++)
    if(a[i][j] == 'T')
      p = &a[i][j];

a[i][j]的类型为char，p的类型为char *，其中保存一个地址.要获取变量的地址，请在其前面加上&.

a[i][j] is of type char and p is of type char *, which holds an address. To get the address of a variable, prepend it with &.

指针上的*运算符以相反的方式工作.如果您想找回'T'，请使用:

The * operator on a pointer works the other way round. If you would want to get the 'T' back, you'd use:

 char theT = *p;

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