通过指针制作字符串 [英] Making strings by pointers

问题描述

我了解到指针指向内存地址，因此我可以使用它来更改在该地址设置的值.像这样:

I have learned that a pointer points to a memory address so i can use it to alter the value set at that address. So like this:

int *pPointer = &iTuna;

pPointer在这里的存储器地址为iTuna.因此，我们可以使用pPointer更改iTuna处的值.如果我打印pPointer，则打印内存地址，如果我打印*pPointer，则打印iTuna处的值

pPointer here has the memory address of iTuna. So we can use pPointer to alter the value at iTuna. If I print pPointer the memory address gets printed and if I print *pPointer then the value at iTuna gets printed

现在看这个程序

    char* pStr= "Hello !";
cout<< pStr << endl;
cout<< *pStr << endl;
system("PAUSE");
return 0;

这里有很多我不明白的东西:

There are a lot of stuff I don't understand here:

1. 在你好！"中每个字母分别存储，一个指针保存一个存储器地址.那么pStr如何指向所有字母.

另外，当我打印出pStr时，它会打印 Hello！，而不是内存地址.

Also When I print out pStr it prints Hello !, not a memory address.

当我打印出*pStr时，它也打印出了 H ，但并不是pStr所指的全部.

And when I print out *pStr it prints out H only not all what pStr is pointing too.

我真的不明白，这是我的担忧.希望有人可以向我解释这是如何工作的广告，帮助我理解

I really can't understand and these are my concerns. I hope someone can explain to me how this works ad help me understand

推荐答案

1. "Hello !"是类型为char const[8]且值为{ 'H', 'e', 'l', 'l', 'o', ' ', '!', 0 }的数组. pStr是指向其第一个元素的指针；它的最后一个元素的值为0.

1. "Hello !" is an array of type char const[8] and value { 'H', 'e', 'l', 'l', 'o', ' ', '!', 0 }. pStr is a pointer to its first element; its last element has the value 0.

iostreams库中有一个用于char const *参数的重载，该参数将ar­ gu­ ment视为指向数组第一个元素的指针，并打印每个元素，直到遇到零为止. (用通俗的说法是"Null-ter­ mi­ nat­ ed字符串".)

There is an overload in the iostreams library for a char const * argument, which treats the ar­gu­ment as a pointer to the first element of an array and prints every element until it encounters a zero. ("Null-ter­mi­nat­ed string" in colloquial parlance.)

解引用指向数组第一个元素的指针会为您提供数组的第一个元素，即'H'.等同于pStr[0].

Dereferencing the pointer to the first element of an array gives you the first element of the array, i.e. 'H'. This identical to pStr[0].

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