在没有指针算术的情况下将格式化的字符串追加到C(不是C ++)中的字符串? [英] Append Formatted String to String in C (not C++) Without Pointer Arithmetic?

问题描述

编写了一个非常简单的C函数来说明我想简化的内容:

Wrote a very simple C function to illustrate what I would like to simplify:

void main(int argc, char *argv[]){
    char *me="Foo";
    char *you="Bar";
    char us[100];
    memset(us,100,0x00);

    sprintf(us,"You: %s\n",you);
    sprintf(us+strlen(us),"Me: %s\n",me);
    sprintf(us+strlen(us),"We are %s and %s!\n",me,you);
    printf(us);
}

似乎应该有一个标准的库函数来处理我正在使用sprintf进行的操作并推进指针，不是吗?自从我做了任何数量的C以来已经年了.

It seems like there should be a standard library function to handle what I'm doing with sprintf and advancing the pointer, no? Has been years since I've done any amount of C...

谢谢， -aj

推荐答案

sprintf返回写入的非NUL字符的数量.

sprintf returns the number of non-NUL characters written.

int len = 0;
len += sprintf(us+len, ...);
len += sprintf(us+len, ...);
...

这篇关于在没有指针算术的情况下将格式化的字符串追加到C(不是C ++)中的字符串?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！