如何创建指向成员函数的函数指针? [英] How create a function pointer to point a member function?

问题描述

代码:

struct A
{
    void* f(void *)
    {

    }
};
int main()
{
    void * (*fp)(void *);
    fp = &A::f;
}

编译:

|12|error: cannot convert 'void* (A::*)(void*)' to 'void* (*)(void*)' in assignment|

我尝试了很多方法，但是都失败了……该怎么做?

I have tried many ways, but all failed... How to do that?

推荐答案

对于常规成员指针，您需要声明其属于指针类型的成员的类型；

For a regular member pointer, you'll need to declare the type it's a member of on the pointer type;

int main()
{
    void * (A::*fp)(void *);
    fp = &A::f;
}

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