C函数删除字符串中的元音不起作用? [英] C function to remove vowels in a string not working?

问题描述

这是我删除字符串中元音的功能；

Here is my function to remove the vowels in a string;

char *removeVowels(char *inString) {

    int count = 0; //to count the non vowel characters

    for (int i = 0; inString[i]; i++)
        if (inString[i] != 'a' || inString[i] != 'e' || inString[i] != 'u' || inString[i] != 'o' || inString[i] != 'i')
            inString[count++] = inString[i]; //if character is not a vowel placed at count++  

    inString[count] = '\0';

    return inString;
}

问题在于它正在返回输入的原始字符串.有什么想法吗?

The problem is that it is returning the original string inputted. Any ideas?

推荐答案

||和&&运算符之间存在混淆.您要测试字符是否与'a' AND 和'e'等不同

There is a confusion between the || and && operators. You want to test that the character is different from 'a' AND different from 'e' etc.

这是修改后的版本:

char *removeVowels(char *inString) {
    int count = 0; // index for preserved characters

    for (int i = 0; inString[i]; i++) {
        if (inString[i] != 'a' && inString[i] != 'e' && inString[i] != 'i'
        &&  inString[i] != 'o' && inString[i] != 'u') {
            inString[count++] = inString[i]; // copy the non-vowel character
        }
    }
    inString[count] = '\0';  // set the null terminator.

    return inString;
}

但是请注意，此功能不会删除大写元音，并且y是否应被视为元音仍有待确定.

Note however that uppercase vowels are not removed by this function, and whether y should be considered a vowel remains to be decided.

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