C＃中 - 如何删除元音字符串数组？ [英] c#-how to delete vowels in an array of string?

问题描述

using System;    
using System.Collections.Generic;    
using System.Linq;   
using System.Text;    
using System.Threading.Tasks;

namespace myApp  
{    
    class Program
    {
        static void Main(string[] args)
        {
            string[] vowels = new string[]{"A","a","E","e","I","i","O","o","U","u"};
            for(int j=0;j<vowels.Length;j++)
            {
                string[] names = new string[5];
                names[0] = "john";
                names[1] = "samuel";
                names[2] = "kevin";
                names[3] = "steve";
                names[4] = "martyn";
            for (int i = 0; i < names.Length; i++)
            {
               if(vowels[j]==names[i])
               {

               }
            }


                Console.WriteLine("The output is:"+names[i]);
            }
                Console.ReadLine();
        }
    }
}

谁能帮助我如何从给定的名字删除元音并在控制台显示它们？

can anyone help me how to delete the vowels from the given names and display them in console?

推荐答案

埃泽尔的答案是这样做的最简洁和正确的方法，但如果你想在和元音你删除，你也可以尝试像过更精细的控制：

Eser's answer is the most succinct and correct way to do this, but in case you want to more fine-grain control over when and which vowels you're removing, you could also try something like:

string[] names = new string[5];
names[0] = "john";
names[1] = "samuel";
names[2] = "kevin";
names[3] = "steve";
names[4] = "martyn";

List<char> vowels = new List<char>("AaEeIiOoUuYy".ToCharArray());

for(int i = 0; i < names.Length; i++) {
    string name = names[i];
    string trimmedName = name;

    foreach(char vowel in vowels) {
        int vowelIndex;
        while((vowelIndex = trimmedName.IndexOf(vowel)) != -1) {
            trimmedName = trimmedName.Substring(0, vowelIndex) + trimmedName.Substring(vowelIndex + 1);
        }

    }
    name = trimmedName;
}

这是一个比较明确的，更少的高性能，并且肯定更难看，但 - - 所以你可能想要去与原来的解决方案

This is a bit more explicit, less performant, and definitely more ugly though -- so you may want to go with the original solution.

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