更改PopupWindow的重力 [英] Change gravity of PopupWindow
本文介绍了更改PopupWindow的重力的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个必须显示弹出窗口的按钮.并且弹出窗口必须与按钮的右侧对齐.这就是我的方法.
I have a button that must show a popup window. And the popup window must be aligned with the right side of the button. That's how I do it.
button.setOnClickListener( new View.OnClickListener() {
@Override
public void onClick( final View view ) {
if(popup == null) {
final View view = getLayoutInflater().inflate(R.layout.popup, null);
popup = new PopupWindow(view);
}
if(popup.isShowing()) {
popup.dismiss();
} else {
popup.setInputMethodMode(PopupWindow.INPUT_METHOD_NEEDED);
popup.setFocusable(true);
popup.setWindowLayoutMode(ViewGroup.LayoutParams.WRAP_CONTENT,
ViewGroup.LayoutParams.WRAP_CONTENT);
popup.showAsDropDown(button, 0, 0);
}
}
} );
此代码可以正常工作,但弹出窗口与按钮的左侧对齐.有没有简单的方法可以更改PopupWindow的重力?
This code works fine but the popup window is aligned with the left side of the button. Is there an easy way to change gravity of PopupWindow?
推荐答案
我找到的最简单的方法是指定x-offset参数:
The easiest way I've found is to specify the x-offset parameter:
final View view = popup.getContentView();
view.measure(View.MeasureSpec.UNSPECIFIED, View.MeasureSpec.UNSPECIFIED);
popup.showAsDropDown(button, button.getWidth() - view.getMeasuredWidth(), 0);
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