six.moves.builtins.range在Python 2和Python 3中不一致 [英] six.moves.builtins.range is not consistent in Python 2 and Python 3

问题描述

对于很大的整数范围，应使用xrange(Python 2)，在Python 3中将其重命名为range.我认为模块six可以提供一致的编写原因.

For a very large integer range, xrange (Python 2) should be used, which is renamed to range in Python 3. I assumed module six can provide a consistent why of writing.

但是我发现six.moves.builtins.range在Python 2中返回一个列表，在Python 3中返回一个可迭代的非列表对象，就像名称range一样.

But I found six.moves.builtins.range returns a list in Python 2 and an iterable non-list object in Python 3, just as the name range does.

此外，six.moves.builtins.xrange在Python 2中不存在.

Also, six.moves.builtins.xrange does not exist in Python 2.

我在six中使用了错误的功能吗?还是六个根本不提供range和xrange函数的解决方案?

Was I using the wrong function in six? Or does six simply not provide a solution for the range and xrange functions?

我知道我可以测试sys.version[0]并相应地重命名该功能.我只是在寻找不要重复自己"的解决方案.

I know I can test sys.version[0] and rename the function accordingly. I was just looking for a "Don't Repeat Yourself" solution.

如吉尔森所言:

>>> import six 
>>> six.moves.range
AttributeError: '_MovedItems' object has no attribute 'range'

是与six的版本有关的东西，还是没有six.moves.range这样的东西?

Is it something related to the version of six, or is there no such thing as six.moves.range?

推荐答案

我相信您只想要six.moves.range.不是，six.moves.builtins.range.

I believe you just want six.moves.range. Not, six.moves.builtins.range.

>>> # tested on python2.x..
>>> import six.moves as sm
>>> sm.range
<type 'xrange'>

此处的原因是six.moves.builtins是与版本无关的内置"模块.这仅使您可以访问内置函数-实际上并不会更改任何内置函数 .

The reason here is that six.moves.builtins is the version agnostic "builtins" module. That just gives you access to the builtins -- it doesn't actually change what any of the builtins are.

通常，在这种情况下，我不需要引入外部依赖关系.我通常只是在源文件的顶部添加这样的内容:

Typically, I don't feel the need to introduce the external dependency in cases like this. I usually just add something like this to the top of my source file:

try:
    xrange
except NameError:  # python3
    xrange = range

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