pthread_create没有参数? [英] pthread_create with no arguments?

问题描述

我想创建一个没有函数参数的线程，但我一直遇到严重困扰我的错误，因为我无法获得一些超级简单的方法来正确工作

I want to create a thread with no function arguments but I keep getting errors that are seriously bugging me because I cant get something super simple to work right

这里是我的代码:

#include<stdio.h>
#include<array>
#include<pthread.h>
#include<fstream>
#include<string>

void *showart(NULL);

int main(int argc,  char** argv){
    pthread_t thread1;
    pthread_create( &thread1, NULL, showart, NULL);
    getchar();
    return 0;
}

void *showart(NULL)
{
    std::string text;
    std::ifstream ifs("ascii");
    while(!ifs.eof()) 
    {
      std::getline(ifs,text);
      printf(text.c_str());
    }
}

它给出了错误:

main.cpp:11:50: error: invalid conversion from ‘void*’ to ‘void* (*)(void*)’ [-fpermissive]

推荐答案

您的函数必须与pthread匹配.这意味着它需要获取并返回void*.改为使用void* showart(void*);.

Your function has to match the pthread one. Meaning it needs to take and return a void*. Use void* showart(void*); instead.

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