如何在R中将PostgreSQL的bytea列十六进制解码为int16 / uint16？ [英] How to decode PostgreSQL bytea column hex to int16/uint16 in r?

问题描述

我有一些图像数据作为bytea存储在PostgreSQL数据库表列中。我也有关于数据的元数据，可用于解释它，相关的是图像尺寸和类。类包括int16，uint16。我找不到在R中正确解释带符号/无符号整数的任何信息。

I have some image data stored in a PostgreSQL database table column as bytea. I also have metadata about the data for use in interpreting it, relevant ones being image dimensions and class. Classes include int16, uint16. I cannot find any information on interpreting signed/unsigned ints correctly in R.

我正在使用RPostgreSQL将数据提取到R中，并且我想在R中查看图像。

I am using RPostgreSQL to pull the data into R and I want to view the image in R.

MWE：

# fakeDataQuery <- dbGetQuery(conn, 
#     'select byteArray, ImageSize, ImageClass from table where id = 1')

# Example 1 (no negative numbers)
# the actual byte array shown in octal sequences in pgadmin (1.22.2) Query Output is: 
# "\001\000\002\000\003\000\004\000\005\000\006\000\007\000\010\000\011\000"

# but RPostgreSQL returns the hex-encoded version:
byteArray <- "\\x010002000300040005000600070008000900"
ImageSize <- c(3, 3, 1)
ImageClass <- 'int16'

# expected result 
> array(c(1,2,3,4,5,6,7,8,9), dim=c(3,3,1))
#   , , 1
#
#        [,1] [,2] [,3]
#[1,]    1    4    7
#[2,]    2    5    8
#[3,]    3    6    9

# Example 2: (with negtive numbers)
byteArray <- "\\xffff00000100020003000400050006000700080009000a00"
ImageSize <- c(3, 4, 1)
ImageClass <- 'int16'
# expectedResult 
> array(c(-1,0,1,2,3,4,5,6,7,8,9,10), dim=c(3,4,1))
#, , 1
#
#     [,1] [,2] [,3] [,4]
#[1,]   -1    2    5    8
#[2,]    0    3    6    9
#[3,]    1    4    7   10

我尝试过的操作：

来自PostgreSQL的bytea数据是一个长字符串，编码为十六进制，您可以通过 \\x来辨别预先添加到它中（我想还有一个 \ 用来转义现有的吗？）：> https://www.postgresql.org/docs/9.1/static/datatype-binary.html （请参阅：第8.4.1节字节十六进制格式）

The bytea data from PostgreSQL is a long character string of digits encoded as "hex", which you can tell by the \\x pre-pended to it (I believe there is an extra \ for escaping the existing one?): https://www.postgresql.org/docs/9.1/static/datatype-binary.html (see: section 8.4.1. 'bytea Hex format')

将十六进制解码回原始类型（基于ImageClass的 int16）

Decode 'hex' back to the original type ('int16' based on ImageClass)

每个同一网址以上，十六进制编码使用每个字节2个十六进制数字。因此，我需要将编码的byteArray拆分为适当的长度子字符串，请参见：此链接

Per the same url above, hex encoding uses '2 hexadecimal digits per byte'. So I need to split the encoded byteArray into the appropriate length substrings, see: this link

# remove the \\x hex encoding indicator(s) added by PostgreSQL
byteArray <- gsub("\\x", "", x = byteArray, fixed=T)

l <- 2  # hex digits per byte (substring length)
byteArray <- strsplit(trimws(gsub(pattern = paste0("(.{",l,"})"), 
                                  replacement = "\\1 ", 
                                  x = byteArray)), 
                      " ")[[1]]

# for some reason these appear to be in the opposite order than i expect
# Ex: 1 is stored as '0100' rather than '0001'
# so reverse the digits (int16 specific)
byteArray <- paste0(byteArray[c(F,T)],byteArray[c(T,F)])

# strtoi() converts a vector of hex values given a decimal base
byteArray <- strtoi(byteArray, 16L)

# now make it into an n x m x s array,
# e.g., 512 x 512 x (# slices)
V = array(byteArray, dim = ImageSize)

此解决方案有两个问题：

There are two problems with this solution:

1. 不适用于有符号类型，因此负整数值将被解释为无符号值（例如，'ffff'为-1（int16）但65535（uint16）和strtoi（）将始终返回65535。）


2. 当前仅针对int16进行编码，并且需要一些额外的代码才能与其他类型（例如int32，int64）一起使用

任何人都可以使用带符号类型的解决方案吗？

Anyone have a solution that would work with signed types?

推荐答案

您可以从此转换功能开始，用更快的 strsplit 并在结果上使用 readBin

You can start with this conversion function, substitute a faster strsplit and use readBin on the result:

byteArray <- "\\xffff00000100020003000400050006000700080009000a00"

## Split a long string into a a vector of character pairs
Rcpp::cppFunction( code = '
CharacterVector strsplit2(const std::string& hex) {
  unsigned int length = hex.length()/2;
  CharacterVector res(length);
  for (unsigned int i = 0; i < length; ++i) {
    res(i) = hex.substr(2*i, 2);
  }
  return res;
}')

## A function to convert one string to an array of raw
f <- function(x)  {
  ## Split a long string into a a vector of character pairs
  x <- strsplit2(x)
  ## Remove the first element, "\\x"
  x <- x[-1]
  ## Complete the conversion
  as.raw(as.hexmode(x))
}

raw <- f(byteArray)
# int16
readBin(con = raw,
        what = "integer",
        n = length(raw) / 2,
        size = 2,
        signed = TRUE,
        endian = "little")
# -1  0  1  2  3  4  5  6  7  8  9 10

# uint16
readBin(con = raw,
        what = "integer",
        n = length(raw) / 2,
        size = 2,
        signed = FALSE,
        endian = "little")
# 65535     0     1     2     3     4     5     6     7     8     9    10

# int32
readBin(con = raw,
        what = "integer",
        n = length(raw) / 4,
        size = 4,
        signed = TRUE,
        endian = "little")
# 65535 131073 262147 393221 524295 655369

这不适用于 uint32 和（u）int64 ，因为R使用 int32 内部。但是，R也可以使用数字来存储2 ^ 52以下的整数。这样我们就可以使用：

This won't work for uint32 and (u)int64, though, since R uses int32 internally. However, R can also use numerics to store integers below 2^52. So we can use this:

# uint32
byteArray <- "\\xffffffff0100020003000400050006000700080009000a00"
int32 <- readBin(con = f(byteArray),
                 what = "integer",
                 n = length(raw) / 4,
                 size = 4,
                 signed = TRUE,
                 endian = "little")

ifelse(int32 < 0, int32 + 2^32, int32)
# 4294967295     131073     262147     393221     524295     655369

对于 gzip 压缩数据：

# gzip
byteArray <- "\\x1f8b080000000000000005c1870100200800209a56faffbd41d30dd3b285e37a52f9d033018818000000"
con <- gzcon(rawConnection(f(byteArray)))
readBin(con = con,
        what = "integer",
        n = length(raw) / 2,
        size = 2,
        signed = TRUE,
        endian = "little")
close(con = con)

小号由于这是真正的联系，我们必须确保将其关闭。

Since this is a real connection, we have to make sure to close it.

这篇关于如何在R中将PostgreSQL的bytea列十六进制解码为int16 / uint16？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！