如何从PostgreSQL以UTC偏移量获取ISO格式的时间？ [英] How to get time in ISO format with UTC offset from PostgreSQL?

问题描述

在python中，我可以这样获得ISO格式的不同时区的时间：

In python I can get time for different time zones in ISO format like this:

>>> import datetime
>>> import pytz
>>> datetime.datetime.now(tz=pytz.timezone('America/New_York')).isoformat()
'2019-03-15T04:01:23.919800-04:00'
>>> datetime.datetime.now(tz=pytz.timezone('Asia/Bangkok')).isoformat()
'2019-03-15T15:01:23.919800+07:00'

现在我需要以相同的格式从postgresql获取时间戳。经过研究后，我得出的最好结论是：

Now I need to get timestamps from postgresql in the same format. After some research the best I've come up with is this:

postgres=# set time zone 'America/New_York';
SET
postgres=# select to_json(now());
      to_json               
------------------------------------
 "2019-03-15T04:32:13.628323-04:00"

是否可以做到这一点而无需更改数据库会话的时区？像这样的东西：

Is it possible to do that without changing the time zone of the database session? Something like:

postgres=# select to_json(now() at time zone 'America/New_York') NYC,
postgres-# to_json(now() at time zone 'Asia/Bangkok') Bangkok;
           nyc                |           bangkok         
------------------------------+------------------------------
 "2019-03-15T04:41:07.789954" | "2019-03-15T15:41:07.789954"

否则是正确的，但缺少UTC偏移量。

which is otherwise correct but missing the UTC offset.

推荐答案

如何？

SELECT current_timestamp AT TIME ZONE 'America/New_York'
       || replace('+' || to_char(current_timestamp AT TIME ZONE 'America/New_York'
                                 - current_timestamp AT TIME ZONE 'UTC',
                                'HH24:MMFM'),
                  '+-', '-');

             ?column?             
----------------------------------
 2019-03-15 05:43:38.901642-04:00
(1 row)

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