使zend Framework 2在没有虚拟主机的情况下工作 [英] Make zend framework 2 work without Virtual Host

问题描述

我已经使用Zend Framework 2完成了我的第一个Web应用程序，并且准备将其在线。但可能是网络托管服务商不允许我更改我的虚拟主机配置！允许使用.htaccess文件。

I had finished my first web application using Zend Framework 2 and I'm about to put it online. But may web host doesn't allow me to change my vhost configuration! The .htaccess file is allowed.

我在公用文件夹中的.htaccess文件如下：

My .htaccess file in Public folder is like this:

RewriteEngine On
# The following rule tells Apache that if the requested filename
# exists, simply serve it.
RewriteCond %{REQUEST_FILENAME} -s [OR]
RewriteCond %{REQUEST_FILENAME} -l [OR]
RewriteCond %{REQUEST_FILENAME} -d
RewriteRule ^.*$ - [NC,L]
# The following rewrites all other queries to index.php. The 
# condition ensures that if you are using Apache aliases to do
# mass virtual hosting, the base path will be prepended to 
# allow proper resolution of the index.php file; it will work
# in non-aliased environments as well, providing a safe, one-size 
# fits all solution.
RewriteCond %{REQUEST_URI}::$1 ^(/.+)(.+)::\2$
RewriteRule ^(.*) - [E=BASE:%1]
RewriteRule ^(.*)$ %{ENV:BASE}index.php [NC,L]

我的文件夹目录结构是这样的：

My Folder Directory Structure is like this:

 -ProjectName  
  -config
  -module
  -vendor
    - zendframework
  -public
    - css
    - img
    - JS
    - index.php 

Index.php文件：

Index.php File:

<?php
/**
 * This makes our life easier when dealing with paths. Everything is relative
 * to the application root now.
 */
chdir(dirname(__DIR__));

// Decline static file requests back to the PHP built-in webserver
if (php_sapi_name() === 'cli-server' && is_file(__DIR__ . parse_url($_SERVER['REQUEST_URI'], PHP_URL_PATH))) {
    return false;
}

// Setup autoloading
require 'init_autoloader.php';

// Run the application!
Zend\Mvc\Application::init(require 'config/application.config.php')->run(); 

所以我的问题是：如何仅使用.htaccess文件设置我的ZF2应用程序？

So my question is: How to set up my ZF2 app with only .htaccess files?

我也想在我的网站www.example.com运行时调用默认的 Front模块调用。

Also I want to call default my "Front" Module Call While my site www.example.com run.

您的答案将不胜感激。
预先感谢。

Your Answer will be appreciated. Thanks in advance.

推荐答案

似乎您需要启用mod_rewrite模块并重新启动Apache。

It seems that you need to enable the mod_rewrite module and restart Apache.

Zend Framework 2要求您启用Apache的* mod_rewrite *模块。
* mod_rewrite *模块用于根据某些规则重写请求的URL，
将站点用户重定向到另一个URL。

Zend Framework 2 requires that you have Apache's *mod_rewrite* module enabled. The *mod_rewrite* module is used to rewrite requested URLs based on some rules, redirecting site users to another URL.

在Debian或Ubuntu Linux

要启用Apache mod_rewrite 模块，请键入以下命令：

To enable Apache mod_rewrite module, type the following commands:

cd / etc / apache2 / mods-enabled

sudo ln -s ../mods-available/rewrite.load ./rewrite.load

以上命令创建 mods-enabled 目录中的符号链接，
这样可以在现代版本的Apache Web服务器中启用模块。

The command above creates a symbolic link in the mods-enabled directory, this way you enable modules in modern versions of Apache web server.

最后，重新启动Apache Web服务器以应用您的更改。

Finally, restart Apache web server to apply your changes.

I> Linux中的符号链接是Windows中的快捷方式类似物。

I> A symbolic link in Linux is an analog of a shortcut in Windows.

在Fedora，CentOS或Red Hat Linux中

在这些Linux发行版中， mod_rewrite 默认情况下处于启用状态，因此您无需执行
任何事情。

In these Linux distributions, mod_rewrite is enabled by default, so you don't need to do anything.

编辑配置文件后，通常必须重新启动Apache HTTP Server
才能应用更改。您可以使用以下命令（在Debian或Linux Ubuntu中）执行此操作：

After editing configuration files, you usually have to restart Apache HTTP Server to apply your changes. You do this with the following command (in Debian or Linux Ubuntu):

sudo服务重启apache2

或以下版本（在Fedora，CentOS或Red Hat中）：

or the following (in Fedora, CentOS or Red Hat):

sudo服务重新启动httpd

因此，您应该看到如下输出：

As a result, you should see output like below:

* Restarting web server apache2
apache2: Could not reliably determine the server's fully qualified 
domain name, using 127.0.0.1 for ServerName
  ... waiting apache2: Could not reliably determine the server's fully 
qualified domain name, using 127.0.0.1 for ServerName                   [OK]

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