重复正则表达式捕获组的捕获部分 [英] Capture section of a repeating regex capture group

问题描述

  ^（[az-] +-on-sale（？：,, [az-] +-on-sale）{0，}）[\ /] $ 
  

此正则表达式在htaccess文件中使用，并且匹配这样的模式：

 销售工具，销售糖果，销售食品/ 
  
  ^（（[[az-] +）-on -sale（？：，[az-] +-on-sale）{0，}）[\ /] $ 
  
这样，我将工具隔离在其自己的捕获组中，但第二部分似乎无法做到这一点。 
解决方案
没有短途方法可以做到这一点。但是，您可以定义期望的最大项目数，并为每个项目创建一个可选组。
 
 
 
对于1至3个项目：
  ^（[az-] +）-on-sale（？：（，（az-] +）-on- sale（？：（，（az-] +）on-sale）？）？/ $ 
  
 
 
 
 
 
 
 请求网址 
  http://foo.bar/tools-on-sale，糖果出售，食品出售/ 
  
  htaccess  
  RewriteRule ^（[ az-] +）-on-sale（？：（，[az-] +）-on-sale（？：（，[az-] +）-on-sale）？）？/ $ http：// foo .bar / $ 1 $ 2 $ 3 [L] 
  
  *感谢 @sln 提出改进建议 
 
 
 
 输出网址 
  http://foo.bar/tools,candy,fo od 
  
 
 
 
 
 
 
但是，如果您需要的分隔符不是逗号，如果您的商品少于3个，则会生成空令牌。例如：
  http://foo.bar/tools-- 
  
如果必须避免，则需要为每个项目数创建1条规则：
  RewriteRule ^（[[az-] +）待售，（[az-] +）待售，（[ az-] +）-on-sale / $ http://foo.bar/$1-$2-$3 [L] 
 RewriteRule ^（[az-] +）-on-sale，（[[az-] +）-on-sale / $ http://foo.bar/$1-$2 [L] 
 RewriteRule ^（[az-] +）-on-sale / $ http://foo.bar/$1 [L] 
  
 
^([a-z-]+-on-sale(?:,[a-z-]+-on-sale){0,})[\/]$
This regex is used in a htaccess file and matches a pattern such as this one:
tools-on-sale,candy-on-sale,food-on-sale/
I've been wondering whether it's possible or not for me to capture a subsection of a repeated capture group. I want to match the same pattern, but I want to omit the "-on-sale" part in the repeated capture group. I know I can already do this for the first part of the regex:
^(([a-z-]+)-on-sale(?:,[a-z-]+-on-sale){0,})[\/]$
That way I have "tools" isolated in its own capture group, but I can't seem to do with the same with the second part. Is this even doable with a regex?
解决方案
There is not a short way to achieve this. However, you could define a maximimum number of items you should expect, and create one optional group for each.

For 1 to 3 items:
^([a-z-]+)-on-sale(?:(,[a-z-]+)-on-sale(?:(,[a-z-]+)-on-sale)?)?/$




Request url
http://foo.bar/tools-on-sale,candy-on-sale,food-on-sale/
htaccess
RewriteRule ^([a-z-]+)-on-sale(?:(,[a-z-]+)-on-sale(?:(,[a-z-]+)-on-sale)?)?/$ http://foo.bar/$1$2$3 [L]
*Thanks to @sln for suggesting an improvement

Output url
http://foo.bar/tools,candy,food




However, if you need a delimiter other than commas, this will generate empty tokens if you have less than 3 items. E.g:
http://foo.bar/tools--
If you must avoid it, you need to create 1 rule for each number of items:
RewriteRule ^([a-z-]+)-on-sale,([a-z-]+)-on-sale,([a-z-]+)-on-sale/$ http://foo.bar/$1-$2-$3 [L]
RewriteRule ^([a-z-]+)-on-sale,([a-z-]+)-on-sale/$ http://foo.bar/$1-$2 [L]
RewriteRule ^([a-z-]+)-on-sale/$ http://foo.bar/$1 [L]


                        
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