java正则表达式捕获组 [英] java regex capture group

问题描述

我试图捕获正确的部分：使用java expr，但在下面的代码中，打印的捕获组是整个字符串，有什么问题？

I am trying to capture the right part after the : using java expr, but in the following code, the printed capture group is the whole string, what's wrong?

String s ="xyz: 123a-45";   
String patternStr="xyz:[ \\t]*([\\S ]+)";
Pattern p = Pattern.compile(patternStr);
Matcher m = p.matcher(s);
//System.err.println(s);
if(m.find()){
    int count = m.groupCount();
    System.out.println("group count is "+count);
    for(int i=0;i<count;i++){
        System.out.println(m.group(i));
    }
}

推荐答案

编号子组以1,0开头是全文。用你的循环直到数+ 1。

Numbering of subgroups starts with 1, 0 is the full text. Just go till count+1 with your loop.

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