“静默地”提取7-Zip文件。 -命令行选项 [英] Extracting a 7-Zip file "silently" - command line option
问题描述
我想在Python脚本中提取 7-Zip 存档。效果很好,只是它会吐出提取细节(在我的情况下这是很大的)。
I want to extract a 7-Zip archive in a Python script. It works fine except that it spits out the extraction details (which is huge in my case).
在提取过程中是否有避免这种冗长信息的方法?我没有找到 7z.exe
的任何静默命令行选项。
Is there a way to avoid this verbose information while extracting? I did not find any "silent" command line option to 7z.exe
.
我的命令是
7z.exe -o some_dir x some_archive.7z
推荐答案
一种可能是使用 popen
,因此其输出将返回到父级进行处理/显示(如果需要),或者完全忽略(创建)您的 popen
对象,其中包含 stdout = PIPE
和 stderr = PIPE
以便能够从孩子那里检索输出。
One possibility would be to spawn the child process with popen
, so its output will come back to the parent to be processed/displayed (if desired) or else completely ignored (create your popen
object with stdout=PIPE
and stderr=PIPE
to be able to retrieve the output from the child).
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