{error =“ invalid_request”; “ error_description” =“缺少必需的参数：grant_type”；迅速 [英] { error = "invalid_request"; "error_description" = "Required parameter is missing: grant_type"; } In swift

问题描述

I am trying with this but every time I will get 

{     error = "invalid_request";     "error_description" = "Required parameter is missing: grant_type"; }

Request String: 

let headers    = [ "Content-Type" : "application/x-www-form-urlencoded"]

let urlString = "https://accounts.google.com/o/oauth2/token?"

Alamofire.request(urlString, method: .post, parameters: ["grant_type":"authorization_code","code":"4/FAOYR1mQo1lN1Gdg9jDnigwZ8RP76NUrqPbYZlMCSP28","client_id":"387376833747-12pbtud9tepr4di0insdhc0d4qpf5e9m.apps.googleusercontent.com","client_secret":"xOacVhLavM9fH8SpOK4I2dRJ","redirect_uri":"https://stackoverflow.com"], encoding: JSONEncoding.default, headers : headers)
            .responseJSON { response in
                print(response)
                print(response.result)
        }

也可以尝试传递这样的请求参数，但对我仍然不起作用。

Also try with passing request parameter like this but still doesn't work for me.

推荐答案

您不能使用以下命令发送附加参数发送请求时的网址。
传递参数，如下所示

You can't send appended parameter with url while post request. Pass parameter as below this

  let headers    = [ "Content-Type" : "application/x-www-form-urlencoded","grant_type" : "authorization_code"" ]

        let urlString = "https://accounts.google.com/o/oauth2/token?"
            Alamofire.request(urlString, method: .post, parameters: ["code":"4/FAOYR1mQo1lN1Gdg9jDnigwZ8RP76NUrqPbYZlMCSP28","client_id":"apps.googleusercontent.com","client_secret":"","redirect_uri":"https://stackoverflow.com"], encoding: JSONEncoding.default, headers : headers)
                .responseJSON { response in
                    print(response)
                    print(response.result)
            }

这篇关于{error =“ invalid_request”; “ error_description” =“缺少必需的参数：grant_type”；迅速的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！