错误“缺少必需的参数:grant_type"使用 Swift 3 [英] Error 'Missing required parameter : grant_type' using Swift 3

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本文介绍了错误“缺少必需的参数:grant_type"使用 Swift 3的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在处理 Twitter API,我想获取 access_Token 但我收到此错误:

I am working on Twitter API and I want to get access_Token but I am getting this error:

{
"errors" : [
  {
    "message" : "Missing required parameter: grant_type",
    "label" : "forbidden_missing_parameter",
    "code" : 170
  }
 ]
}. 

我的要求如下:

let dict = ["grant_type" : "client_credentials"]  

requestPOSTURL("https://api.twitter.com/oauth2/token", params: dict as [String : AnyObject] , headers: ["Authorization" : "Basic " + strHeader, "Content-Type" : "application/x-www-form-urlencoded;charset=UTF-8"], success: { (json) in

        Helper.sharedInstance.Print(json as AnyObject)

    }, failure: {(error) in

        Helper.sharedInstance.Print(error as AnyObject)
    }). 

func requestPOSTURL(_ strURL : String, params : [String : AnyObject]?, headers : [String : String]?, success:@escaping (JSON) -> Void, failure:@escaping (Error) -> Void){
    sessionManager.request(strURL, method: .post, parameters: params, encoding: JSONEncoding.default, headers: headers).responseJSON { (responseObject) -> Void in
        //print(responseObject)
        if responseObject.result.isSuccess {
            let resJson = JSON(responseObject.result.value!)
            success(resJson)
        }
        if responseObject.result.isFailure {
            let error : Error = responseObject.result.error!
            failure(error)
        }
    }
}

这里我正在尝试获取 access_Token (OAuth),但由于出现上述错误而无法获取.

Here I am trying to get access_Token (OAuth) but not able to get because above errors are coming.

推荐答案

我也遇到过类似的问题,并且通过原生 NSMutableURLRequest 解决了这个问题.https://stackoverflow.com/a/59472862/1528061

I have faced the similar issue, and it get fixed with native NSMutableURLRequest. https://stackoverflow.com/a/59472862/1528061

这篇关于错误“缺少必需的参数:grant_type"使用 Swift 3的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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