使用setRepeating（）方法知道下一个警报时间 [英] to know next alarm time using setRepeating() method

问题描述

我有9:00 AM，1：00 PM，7：00 PM之类的时间，我每天设置3个待处理的意图，这些意图是使用setRepeating（）方法递归触发的。

I have times like 9:00 AM, 1:00 PM, 7:00 PM, where I set 3 pending intents that are recursively triggered using setRepeating() method every day.

（这里我将所有这些待处理的意图唯一请求代码保存在本地SQLite数据库中）

(Here I am saving all these pending intents unique request codes in the local SQLite database)

这里，每当触发警报时，我都想知道下一个将要触发并显示给用户的警报

Here, whenever an alarm is triggered I would like to know the next alarm that is going to be triggered and show to user

示例。现在，警报在上午9:00触发，此时我应该向用户显示下一个警报将在1:00 PM触发。
有什么解决方法可以使我获得下一个警报详细信息。

Example.. Now an alarm was triggered at 9:00 AM and at this time I should display the user that the next alarm is going to be triggered at 1:00 PM. Is there any solution that I could get the next alarm details.

希望我能正确传达。如有疑问，请告诉我

Hope I conveyed correctly.If any queries please let me know

谢谢！

推荐答案

正如我在另一个问题中所说，您无法获得来自AlarmManager的信息。您需要将信息自己存储在SharedPreferences中，以便以后使用。

As I said in the other question, you cannot get this information from the AlarmManager. You would need to store the information yourself in a SharedPreferences so that you can refer to it later.

例如，每当闹钟响起时，您都可以将SharedPreferences更新为指示下一次重复的时间。

For example, whenever your alarm goes off, you can update the SharedPreferences to indicate when the next repeat should happen.

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