在Java中更改字符串列表中的特定字符 [英] Changing specific characters in List of Strings in Java

问题描述

背景故事：

List<String> alphabet; // (contains 26 unique characters as elements, for example 
    // qwertyuiosapdfghjklzcxvbnm)

List<String> wordsToArrange; // contains words as elements, for example: 

 - apple 
 - stream
 - posthouse
 - sea
 - seed

我需要根据我制作的字母排列单词。

I need to arrange the words according to the alphabet I have made.

我之前为循环做了很多工作，但是我从上一个问题的答案中得到了一个想法进行映射就像这样：

I was doing huge and many for loops before, but I got an idea from an answer to a previous question to map it like:

alphabet(0) --> "a";
alphabet(1) --> "b";
.................
alphabet(25) --> "z";

所以话会变，苹果会变成苹果---> kjjsc

然后，我可以使用 collection.sort 并创建一个新列表，然后将单词转换回正常状态。.

So the words would change, apple would become apple ---> kjjsc
Then I could use collection.sort and to a new list, and then convert the words back to normal..

for(int i = 0; i < wordsToArrange.size(); i++){

List<String> charArray = new ArrayList<String>(Arrays.asList(wordsToArrange.get(i).split("")));

int arraySize = wordsToArrange.get(i).length();

Collections.replaceAll(charArray, alphabet.get(0), "a");
Collections.replaceAll(charArray, alphabet.get(1), "b");
Collections.replaceAll(charArray, alphabet.get(2), "c");
Collections.replaceAll(charArray, alphabet.get(3), "d");
Collections.replaceAll(charArray, alphabet.get(4), "e");
Collections.replaceAll(charArray, alphabet.get(5), "f");
Collections.replaceAll(charArray, alphabet.get(6), "g");
Collections.replaceAll(charArray, alphabet.get(7), "h");
Collections.replaceAll(charArray, alphabet.get(8), "i");
Collections.replaceAll(charArray, alphabet.get(9), "j");
Collections.replaceAll(charArray, alphabet.get(10), "k");
Collections.replaceAll(charArray, alphabet.get(11), "l");
Collections.replaceAll(charArray, alphabet.get(12), "m");
Collections.replaceAll(charArray, alphabet.get(13), "n");
Collections.replaceAll(charArray, alphabet.get(14), "o");
Collections.replaceAll(charArray, alphabet.get(15), "p");
Collections.replaceAll(charArray, alphabet.get(16), "q");
Collections.replaceAll(charArray, alphabet.get(17), "r");
Collections.replaceAll(charArray, alphabet.get(18), "s");
Collections.replaceAll(charArray, alphabet.get(19), "t");
Collections.replaceAll(charArray, alphabet.get(20), "u");
Collections.replaceAll(charArray, alphabet.get(21), "v");
Collections.replaceAll(charArray, alphabet.get(22), "w");
Collections.replaceAll(charArray, alphabet.get(23), "x");
Collections.replaceAll(charArray, alphabet.get(24), "y");
Collections.replaceAll(charArray, alphabet.get(25), "z");

StringBuilder listString = new StringBuilder();
for (String s : charArray)
    listString.append(s+"");
System.out.println(listString);         

这似乎会覆盖所有字符，因此输出为：

This seems to overwrite all the characters so the output is:

rqqsw
sezwrz
qisepiosw
swr
swwz

今天我的大脑雾气很大，我想我可以将这种方法推到最后，直到我找到某种解决方案为止，但这似乎并不是有效的解决方法做吧。有什么想法吗？

My brain is quite foggy today and I think I could push this way to the end till I have some kind of solution, but this does not seem like the efficient way to do it. Any ideas?

此刻，我从列表中取出一个单词，将其放入一个char数组中，这样我就可以分别更改字符，然后将新的char数组放回去字符串，然后我将其在列表中替换为一个新单词（或创建一个新列表）。仔细阅读所有单词后，我将得到一个列表。我会在其上使用 collection.sort ，然后再转换回普通单词，但现在顺序正确。

At the moment I take a word from a list, make it into a char array so I could change very character separately, then put the new char array back to string, and then I would replace it in the list with a new word (or make a new list). After I have gone through all the words I would have a list. I would use collection.sort on it and then convert back to normal words, but now in correct order.

我的第一个问题：
根据Java中的字符列表对单词列表进行排序

推荐答案

问题是您所使用的字符

最简单的方法是通过一次更改字符。

The simplest approach is to change the characters in a single pass.

public static String encode(String input, String dict) {
    StringBuilder sb = new StringBuilder();
    for (char ch : input.toCharArray()) {
        int index = dict.indexOf(ch); // look for the character
        if (index >= 0)
           sb.append((char) ('a' + index)) // use the matching char instead
        else
           sb.append(ch); // otherwise copy untranslated.
    }
    return sb.toString();
}

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