如何知道引起异常的确切代码行？ [英] How to know the exact line of code where an exception has been caused?

问题描述

如果我自己生成一个异常，则可以在异常中包含任何信息：许多代码行和源文件的名称。像这样：

If I generate an exception on my own, I can include any info into the exception: a number of code line and name of source file. Something like this:

throw std::exception("myFile.cpp:255");

但是未处理的异常或不是由我生成的异常是什么？

But what's with unhandled exceptions or with exceptions that were not generated by me?

推荐答案

似乎每个人都在尝试改进您的代码以在代码中引发异常，而没有人在尝试您提出的实际问题。

It seems everyone is trying to improve your code to throw exceptions in your code, and no one is attempting the actual question you asked.

这是因为无法完成。如果引发异常的代码仅以二进制形式显示（例如，以LIB或DLL文件形式），则行号消失了，无法将对象连接至源代码中的行。

Which is because it can't be done. If the code that's throwing the exception is only presented in binary form (e.g. in a LIB or DLL file), then the line number is gone, and there's no way to connect the object to to a line in the source code.

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