如何在tkinter中大声让无声例外？ [英] How can I make silent exceptions louder in tkinter?

问题描述

如果我从终端运行以下代码，则会在终端中收到一条有用的错误消息：

If I run the following code from a terminal, I get a helpful error message in the terminal:

import Tkinter as tk

master = tk.Tk()

def callback():
    raise UserWarning("Exception!")

b = tk.Button(master, text="This will raise an exception", command=callback)
b.pack()

tk.mainloop()

但是，如果我在没有终端的情况下运行它（例如，通过双击图标），该错误消息就会被抑制。

However, if I run it without a terminal (say, by double-clicking an icon), the error message is suppressed.

在我真正的，更复杂的Tkinter应用程序中，我喜欢GUI有点耐崩溃。我不喜欢用户很难为我提供有用的反馈，以解决由此产生的意外行为。

In my real, more complicated Tkinter application, I like that the GUI is a little crash-resistant. I don't like that my users have a hard time giving me useful feedback to fix the resulting unexpected behavior.

该如何处理？在Tkinter应用程序中是否存在公开跟踪或stderror或其他内容的标准方法？我正在寻找比在任何地方都放置try / except更优雅的东西。

How should I handle this? Is there a standard way to expose tracebacks or stderror or whatnot in a Tkinter application? I'm looking for something more elegant than putting try/except everywhere.

编辑：Jochen Ritzel在下面给出了一个很好的回答，它弹出一个警告框，并提到附加它上课。只是为了明确起见：

Jochen Ritzel gave an excellent answer below that pops up a warning box, and mentioned attaching it to a class. Just to make this explicit:

import Tkinter as tk
import traceback, tkMessageBox

class App:
    def __init__(self, master):
        master.report_callback_exception = self.report_callback_exception
        self.frame = tk.Frame(master)
        self.frame.pack()
        b = tk.Button(
            self.frame, text="This will cause an exception",
            command=self.cause_exception)
        b.pack()

    def cause_exception(self):
        a = []
        a.a = 0 #A traceback makes this easy to catch and fix

    def report_callback_exception(self, *args):
        err = traceback.format_exception(*args)
        tkMessageBox.showerror('Exception', err)

root = tk.Tk()
app = App(root)
root.mainloop()

我剩下的困惑：Jochen提到了可能性不同的异常报告功能的区别nt帧。我还没看到怎么做。

My remaining confusion: Jochen mentions the possibility of having different exception reporting functions in different frames. I don't yet see how to do that. Is this obvious?

推荐答案

有 report_callback_exception 可以做到：

import traceback
import tkMessageBox

# You would normally put that on the App class
def show_error(self, *args):
    err = traceback.format_exception(*args)
    tkMessageBox.showerror('Exception',err)
# but this works too
tk.Tk.report_callback_exception = show_error

如果您未将'Tkinter as tk'导入，然后做

If you didn't import 'Tkinter as tk', then do

Tkinter.Tk.report_callback_exception = show_error

这篇关于如何在tkinter中大声让无声例外？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！