如何在 tkinter 中使无声异常更响亮? [英] How can I make silent exceptions louder in tkinter?

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本文介绍了如何在 tkinter 中使无声异常更响亮?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

如果我从终端运行以下代码,我会在终端中收到有用的错误消息:

If I run the following code from a terminal, I get a helpful error message in the terminal:

import Tkinter as tk

master = tk.Tk()

def callback():
    raise UserWarning("Exception!")

b = tk.Button(master, text="This will raise an exception", command=callback)
b.pack()

tk.mainloop()

但是,如果我在没有终端的情况下运行它(例如,通过双击图标),则会抑制错误消息.

However, if I run it without a terminal (say, by double-clicking an icon), the error message is suppressed.

在我真实的、更复杂的 Tkinter 应用程序中,我喜欢 GUI 有点抗崩溃.我不喜欢我的用户很难给我有用的反馈来修复由此产生的意外行为.

In my real, more complicated Tkinter application, I like that the GUI is a little crash-resistant. I don't like that my users have a hard time giving me useful feedback to fix the resulting unexpected behavior.

我该如何处理?在 Tkinter 应用程序中是否有标准方法来公开回溯或 stderror 或诸如此类的东西?我正在寻找比将 try/except 放在任何地方更优雅的东西.

How should I handle this? Is there a standard way to expose tracebacks or stderror or whatnot in a Tkinter application? I'm looking for something more elegant than putting try/except everywhere.

Jochen Ritzel 在下面给出了一个很好的答案,它弹出了一个警告框,并提到将它附加到一个类中.只是为了明确这一点:

Jochen Ritzel gave an excellent answer below that pops up a warning box, and mentioned attaching it to a class. Just to make this explicit:

import Tkinter as tk
import traceback, tkMessageBox

class App:
    def __init__(self, master):
        master.report_callback_exception = self.report_callback_exception
        self.frame = tk.Frame(master)
        self.frame.pack()
        b = tk.Button(
            self.frame, text="This will cause an exception",
            command=self.cause_exception)
        b.pack()

    def cause_exception(self):
        a = []
        a.a = 0 #A traceback makes this easy to catch and fix

    def report_callback_exception(self, *args):
        err = traceback.format_exception(*args)
        tkMessageBox.showerror('Exception', err)

root = tk.Tk()
app = App(root)
root.mainloop()

我剩下的困惑:Jochen 提到了在不同的框架中有不同的异常报告功能的可能性.我还不知道如何做到这一点.这很明显吗?

My remaining confusion: Jochen mentions the possibility of having different exception reporting functions in different frames. I don't yet see how to do that. Is this obvious?

推荐答案

report_callback_exception可以做到这一点:

import traceback
import tkMessageBox

# You would normally put that on the App class
def show_error(self, *args):
    err = traceback.format_exception(*args)
    tkMessageBox.showerror('Exception',err)
# but this works too
tk.Tk.report_callback_exception = show_error

如果你没有导入'Tkinter as tk',那么做

If you didn't import 'Tkinter as tk', then do

Tkinter.Tk.report_callback_exception = show_error

这篇关于如何在 tkinter 中使无声异常更响亮?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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