在Python中获取异常值 [英] Getting the exception value in Python

问题描述

如果我有该代码：

try:
    some_method()
except Exception, e:

如何获取此异常值（我的意思是字符串
）？

How can I get this Exception value (string representation I mean)?

推荐答案

使用 str

try:
    some_method()
except Exception as e:
    s = str(e)

此外，大多数异常类都具有 args 属性。通常， args [0] 会是错误消息。

Also, most exception classes will have an args attribute. Often, args[0] will be an error message.

请注意，仅使用<$ c如果没有错误消息，$ c> str 将返回一个空字符串，而pyfunc建议使用 repr 至少会显示异常的类。我的看法是，如果要打印出来，它是针对最终用户的，他们不关心类是什么，只想输入错误消息。

It should be noted that just using str will return an empty string if there's no error message whereas using repr as pyfunc recommends will at least display the class of the exception. My take is that if you're printing it out, it's for an end user that doesn't care what the class is and just wants an error message.

它真的取决于您要处理的异常类及其实例化方式。您有什么特别的主意吗？

It really depends on the class of exception that you are dealing with and how it is instantiated. Did you have something in particular in mind?

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