捕获InputMismatchException直到正确为止 [英] Catching an InputMismatchException until it is correct

问题描述

我正在尝试在程序中添加catch块，以处理输入不匹配异常。我将我的第一个设置为在do while循环中工作，以便为用户提供纠正问题的机会。

I am trying add catch blocks to my program to handle input mismatch exceptions. I set up my first one to work inside of a do while loop, to give the user the opportunity to correct the issue.

System.out.print("Enter Customer ID: ");
int custID=0;
do {
    try {
        custID = input.nextInt();
    } catch (InputMismatchException e){
        System.out.println("Customer IDs are numbers only");
    }
} while (custID<1);

就目前而言，如果我尝试输入字母，则会陷入客户的无限循环ID仅是数字。

As it stands, if I try to enter a letter, it goes into an infinite loop of "Customer IDs are numbers only".

我如何使其正常工作？

推荐答案

请注意，当扫描程序引发InputMismatchException时，扫描程序将不会传递导致异常的令牌，因此可以通过其他方法检索或跳过该令牌。

为避免 客户ID仅是数字的无限循环。 ，您需要致电在catch语句中使用input.next（）; 使得可以在控制台中重新输入数字

To avoid "infinite loop of "Customer IDs are numbers only".", You need to call input.next(); in the catch statement to to make it possible to re-enter number in Console

从

声明

catch (InputMismatchException e) {
            System.out.println("Customer IDs are numbers only");

到

catch (InputMismatchException e) {
            System.out.println("Customer IDs are numbers only");
            input.next();
        }

测试示例：

Enter Customer ID: a
Customer IDs are numbers only
b
Customer IDs are numbers only
c
Customer IDs are numbers only
11

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