Java InputMismatchException [英] Java InputMismatchException

问题描述

 线程中的异常
我有这个代码，我想抓住信件异常，主要java.util.InputMismatchException 
在java.util.Scanner.throwFor（Scanner.java:840）
在java.util.Scanner.next（Scanner.java:1461）
 at java.util.Scanner.nextInt（Scanner.java:2091）
在java.util.Scanner.nextInt（Scanner.java:2050）
在exercise_one.Exercise.main（Exercise.java:17） 
  

这里是我的代码：

  System.out.print（输入学生人数）; 
 
 students = input.nextInt（）; 
 
 while（students< = 0）{
 
 try {
 
 System.out.print（Enter the number of students：） ; 
 
 students = input.nextInt（）; 
 
} 
 
 catch（InputMismatchException e）{
 
 System.out.print（输入学生人数）; 
 
} 
} 
  

解决方案

您可以使用do-while循环来消除第一个 input.nextInt（）。

  do {
 try {
 System.out.print（输入学生人数）; 
 students = input.nextInt（）; 
} catch（InputMismatchException e）{
 System.out.print（学生数量无效）; 
} 
 input.nextLine（）; //清除缓冲区
} while（students< = 0）; 
  

因此，所有 InputMismatchException 可以在一个地方。

I have this code and I want to catch the letter exception but it keeps having these errors:

Exception in thread "main" java.util.InputMismatchException
    at java.util.Scanner.throwFor(Scanner.java:840)
    at java.util.Scanner.next(Scanner.java:1461)
    at java.util.Scanner.nextInt(Scanner.java:2091)
    at java.util.Scanner.nextInt(Scanner.java:2050)
    at exercise_one.Exercise.main(Exercise.java:17)

And here is my code:

 System.out.print("Enter the number of students: ");

 students = input.nextInt(); 

 while (students <= 0) {

     try {

        System.out.print("Enter the number of students: ");

        students = input.nextInt();

     }

     catch (InputMismatchException e) {

        System.out.print("Enter the number of students");

     }
 }    

解决方案

You can use a do-while loop instead to eliminate the first input.nextInt().

do {
    try {
        System.out.print("Enter the number of students: ");
        students = input.nextInt();
    } catch (InputMismatchException e) {
        System.out.print("Invalid number of students. ");
    }
    input.nextLine(); // clears the buffer
} while (students <= 0);

Therefore all InputMismatchException can be handled in one place.

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