通过读取double获得java.util.InputMismatchException [英] java.util.InputMismatchException by reading a double

问题描述

当我尝试读取0.6时，出现了java.util.InputMismatchException异常，这是代码的一部分.如您所见，我尝试为练习表重新实现SkipList.

I got the an java.util.InputMismatchException when I try to read 0.6 here is a part of the code. As you can see i try to reimplement a SkipList for a exercise sheet.

public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
        double f = scan.nextDouble();
        impl_with_errors list = new impl_with_errors(f);
        int n = scan.nextInt();


public class impl_with_errors {
    public static double chance;
    public Node list0;
    public Node list1;
    public Node list2;
    public Node list3;
/**
 * the constructor of the skiplist
 * @param p the chance that an element shall be in a higher list
 */
    public impl_with_errors(double p) {
        chance = p;
        list0 = null;
        list1 = null;
        list2 = null;
        list3 = null;
    }

推荐答案

使用逗号作为小数点分隔符，而不是点. 0,6有效

Use a comma as decimal sperator, not a dot. 0,6 works

使用DecimalFormat df = new DecimalFormat("#,#");

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