为什么在此基本Java程序中获得InputMismatchException？ [英] Why get an InputMismatchException in this elementary Java program?

问题描述

String[] names=new String[4];
int[] scores=new int[4];
Scanner keyboard = new Scanner(System.in);
System.out.println("Enter 4 strings and integers:");
for(int i=0;i<4;i++){
  names[i]=keyboard.nextLine();
  scores[i]= keyboard.nextInt();
}

上面是我的简单程序，下面显示了弹出的异常。 / p>

Above is my simple program and the following shows the exception that pops up.

Enter 4 strings and integers:
first
1
second
Exception in thread "main" java.util.InputMismatchException
    at java.util.Scanner.throwFor(Scanner.java:909)
    at java.util.Scanner.next(Scanner.java:1530)
    at java.util.Scanner.nextInt(Scanner.java:2160)
    at java.util.Scanner.nextInt(Scanner.java:2119)
    at Q2.main(Q2.java:15)
Java Result: 1

推荐答案

nextInt 不会占用行尾，而是保留在缓冲区中。因此，当您按下 1 enter 时， 1 会被读入第一个分数，然后将第二个名称设置为空字符串。

nextInt doesn't swallow the end of line, that stays in the buffer. So when you hit 1enter, 1 is read into the first score, then the second name is set to an empty string.

然后解析器尝试解释秒作为 int ，引发异常。

Then the parser tries to interpret second as an int, raising the exception.

您需要在 readInt 之后丢弃当前行。

You'll need to discard the current line after the readInt.

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