访问Visual Studio的$ exception变量 [英] Access Visual Studio's $exception variable

问题描述

我有一种情况，由于抛出异常，正在运行 onClose 事件处理程序。

I have a situation where an onClose event Handler is running due to an exception thrown.

如果我强制它在附加了VS调试器的情况下发生，那么我可以在VS'Locals'中看到一个 $ exception 局部变量，该变量具有（一些）有趣的信息。

If I force it to happen with the VS debugger attached, then I can see in VS 'Locals' a $exception local variable, which has (somewhat) interesting information on it.

但是我不知道如何在代码中获取该异常，以便我可以对其进行记录。 ：（

But I can't figure out how to get at that exception within the code, so that I can log it. :(

• 我的eventHandler的eventArgs只是 Empty 事件。


• 问 Marshall.GetExceptionCode / Pointers（）没给我任何帮助。

• The eventArgs of my eventHandler are just the Empty Event.
• Asking Marshall.GetExceptionCode/Pointers() doesn't give me anything useful.

很明显有人知道此异常，因为VS可以向我显示此异常...我该如何获得该异常？

Evidently something knows about this exception, because VS can show it to me ... how can I get at that exception?

推荐答案

您真正想要的功能不存在，VS神奇地捕获了当前异常并将其放在 $ exception 伪变量中

The capability you really want doesn't exist. VS magically grabs the current exception and puts it in the $exception pseudo variable in order to make your debugging experience better.

在$codeatch中唯一可以访问（在代码中）的地方块，如果要捕获它，则需要在此处完成VS调试器为您提供了更多伪变量： https://docs.microsoft.com/zh-CN/visualstudio/deb ugger / pseudovariables？view = vs-2019

The only place you have access (in your code) to it in in a catch block. If you want to capture it, you need to do it there. There are a bunch more pseudo-variables the VS debugger makes available to you: https://docs.microsoft.com/en-us/visualstudio/debugger/pseudovariables?view=vs-2019

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