使用Process.Start()由外部程序启动我的代码时进行调试 [英] Debugging when my code is started by external program with Process.Start()

问题描述

假设我有一个C#WinForms应用程序，它是由外部程序通过简单地使用Process.Start(MyModule.exe)启动的.

Suppose I have a C# WinForms application and it is started by external program simply by using Process.Start(MyModule.exe).

我尝试使用我的项目属性-> 调试-> 开始操作-> 开始调试代码外部程序(当然还要设置正确的工作目录).

I've tried to debug my code by using My project properties->Debug->Start Action->Start external program (with setting proper Working directory of course).

我的另一尝试是调试-> 附加以处理

My enother attempt was Debug->Attach to process

更新:我的模块和外部程序都使用一种资源.因此，外部程序将其释放，然后调用Process.Start()，等待我的进程退出并再次捕获资源.因此，当您的程序已经运行时，我无法附加.

UPDATE: Both my module and external program use one resource. So external program releases it, then calls Process.Start(), waits for my process to exit ans then capture the resource again. So I can't attach when your program is already running.

它们两者均失败-从未命中 Program.cs 中的断点.

Both of them failed - breakpoint in Program.cs was never hit.

那么，在这种情况下如何调试代码?

So, how can I debug my code in such circumstances?

推荐答案

我知道有两种方法可以轻松解决此问题.第一种方法是让程序请求调试器附加到它，这是它在Main中通过

There are two ways I know of to easily solve this problem. The first way is have your program request a debugger attach to it as the first thing it does in Main via Debugger.Launch()

public static void Main(string[] args)
{
    Debugger.Launch();

    //Rest of your code here
}

这将显示如下所示的对话框

This will make a dialog like the following show up

这将使您可以附加到正在运行的Visual Studio或启动新实例.

This will allow you to attach to your running visual studio or start a new instance.

当您无法使用以前的方法(例如，我认为它在服务内部不起作用)时解决此问题的另一种方法是在代码的开头放置一个循环，该循环将永远循环直到连接了调试器，这使您有足够的时间执行您之前尝试的附加到进程"方法，而不会让程序继续运行.

The other way to solve this when you can't use the previous method (for example I don't think it works inside services) is put a loop at the start of your code that will loop forever until a debugger is attached, this gives you enough time to do the "Attach to process" method you tried earlier without letting the program progress.

public static void Main(string[] args)
{
    while(!Debugger.IsAttached)
    {
        Thread.Sleep(1000); //Sleep 1 second and then check again.
    }

    //Rest of your code here
}

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