固定精度且无句点的十进制自定义格式字符串 [英] decimal custom format string with fixed precision and no period

问题描述

我遇到了一种情况，我认为您无法使用自定义格式字符串.

I've run into a situation which I think is beyond what you can do with custom format strings.

但是我写的代码太过粗糙了，我以为我还是会问.

But the code I've written is so gross I thought I would ask anyway.

我需要的是将小数点显示为6或7位数字的字符串，如下所示:

What I need is for a decimal to be displayed as either a 6 or 7 digit string, like so:

number = 12345.67M
(optional)
tenthousands thousands hundreds tens ones tenths hundredths
     1          2         3      4    5     6        7

这是我为实现此目的而编写的代码:

Here's the code I've written to achieve this:

public static string ConvertDecimalToString(decimal easting, int length)
{
    var formatString = "{0:0000.00}";
    var numberAsString = string.Format(formatString, easting);
    var removePeriod = numberAsString.Replace(".", "");

    if (removePeriod.Length > length)
    {
        return removePeriod.Substring(removePeriod.Length - length, length);
    }
    else
    {
        return removePeriod.PadLeft(length, '0');
    }
}

---

预期的输入和输出:

---

Expected inputs and outputs:

Input           Output(6)    Output(7)
912345.67M      234567       1234567
12345.67M       234567       1234567
1234.56M        123456       0123456
1234.5M         123450       0123450
1234M           123400       0123400
234M            023400       0023400

推荐答案

如果您想将小数12345.67显示为1234567(只需省略小数点)，请使用以下技巧:

If you want a decimal 12345.67displayed as 1234567 (just omit the decimal point) use this trick:

decimal number = 12345.67M;
string s = string.Format("{0:0000000}", number * 100.0);

或

string s = string.Format("{0:F0}", number * 100.0); // zero decimal places

士气:不要摆弄格式化产生的字符串，而是修改输入值，然后让格式化完成其工作.

Morale: Do not fiddle with a string produced from formatting, modify the input value instead and let the formatting do its job.

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