如何在PHP中使用模式生成34个字母数字? [英] How to generate 34 alphanumerics with a pattern in PHP?

问题描述

我想生成34个随机字母(大写和非大写)和数字.在生成34个随机字母数字之前，有一个 pro_sec _ 字，它每次生成时都存在.还有25号和25号26号是 00

I want to generate 34 random letters (capitalized and not) and numbers. Before the generated 34 random alphanumerics there is a word pro_sec_ which is there everytime it generate. And the 25th & 26th is 00

因此，生成的结果将是:(仅作为示例)

So the generated result will be: (just an example)

pro_sec_Vy6Q67sh6HvP90j7gWnq6SxN00p8Gapu66

另一个. pro_sec_6B57nTshusbnay6esjabxns800nGvaz2Lov

第25位和第26位的pro_sec_和00始终相同，其余的仅生成.

The pro_sec_ and the 00 there in 25th and 26th are always the same and the rest are just generated.

推荐答案

高性能解决方案，无需使用任何循环或两次调用该函数:

Performant solution without using any loops or calling the function twice:

$chars = '0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ';
$split = str_split(substr(str_shuffle($chars), 0, 32), 25);
$res = 'pro_sec_'.$split[0].'00'.$split[1];

echo $res; // pro_sec_c8s5iwyQY0nZoJf73EOkC9vqS00dNLWVKg

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