在Firebase Firestore中使用外部排序而不使用使用的查询不等式 [英] Using external orderby without using used query inequality in firebase firestore

问题描述

无论如何，在这个位置上我是否能以第一订单的身份逃脱GeoPoint? 如果我从orderby中删除GeoPoint，则会触发以下错误；如果按照以下说明将GeoPoint设置为第一个orderby，则会误导第二个orderby priceSort.

Is there anyway i can escape GeoPoint as first order in this postion? If i remove GeoPoint from orderby it triggered the below error and if i put the GeoPoint as first orderby, as instructed as below, it mislead the second orderby priceSort..

未捕获的错误:无效的查询.你有一个where过滤器 在'GeoPoint'字段上具有不等式(<，< =，>或> =) 还必须使用"GeoPoint"作为您的第一个Query.orderBy()，但您的第一个 Query.orderBy()放在字段"priceSort"上.

Uncaught Error: Invalid query. You have a where filter with an inequality (<, <=, >, or >=) on field 'GeoPoint' and so you must also use 'GeoPoint' as your first Query.orderBy(), but your first Query.orderBy() is on field 'priceSort' instead.

 const locations=NearBy({
      center:{
        latitude:4*.*****,
        longitude:7*.*****},
      radius:30000})



    var db = firebase.firestore();
    var AdsQry = db.collection("ads");

      AdsQry = AdsQry
        .where('GeoPoint', '>', locations.lesserGeopoint)
        .where('GeoPoint', '<', locations.greaterThan)
        .orderBy('GeoPoint', 'asc');

        AdsQry = AdsQry.where('complete', '==', 'yes')
        //.where('countrycode', '==', 'IT')
        .orderBy('priceSort', 'desc')

    AdsQry.get().then(function(snapshot) {
      snapshot.forEach((doc) => {
        console.log(doc.id+": priceSort="+doc.data().priceSort+" dateSort="+doc.data().dateSort);
      })
    })

推荐答案

您是否尝试过这样做:

 AdsQry
    .where('GeoPoint', '>', locations.lesserGeopoint)
    .where('GeoPoint', '<', locations.greaterThan)
    .where('complete', '==', 'yes')
    //.where('countrycode', '==', 'IT')
    .orderBy('GeoPoint')
    .orderBy('priceSort', 'desc')

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