Ruby Regex捕获两个字符串(包括两个字符串)之间的所有内容 [英] Ruby Regex to capture everything between two strings (inclusive)

问题描述

我正在尝试清理一些HTML并只删除一个标签(我真的很想避免使用nokogiri等).所以我出现了以下要删除的字符串:

I'm trying to sanitize some HTML and just remove a single tag (and I'd really like to avoid using nokogiri, etc). So I've got the following string appearing I want to get rid of:

<div class="the_class>Some junk here that's different every time</div>

此字符串在我的字符串中仅出现一次，因此我想找到一种删除它的方法.我已经尝试过使用正则表达式来捕获所有内容，但是找不到合适的东西.

This appears exactly once in my string, and I'd like to find a way to remove it. I've tried coming up with a regex to capture it all but I can't find one that works.

我已经尝试过/<div class="the_class">(.*)<\/div>/m，并且可以使用，但是它也可以匹配并包含文档中不需要的任何</div>标签，这是我不想要的.

I've tried /<div class="the_class">(.*)<\/div>/m and that works, but it'll also match up to and including any further </div> tags in the document, which I don't want.

关于如何解决此问题的任何想法?

Any ideas on how to approach this?

推荐答案

我相信您正在寻找一种非贪婪的正则表达式，例如:

I believe you're looking for an non-greedy regex, like this:

/<div class="the_class">(.*?)<\/div>/m

请注意添加的?.现在，捕获组将捕获尽可能少的(非贪婪)，而不是捕获尽可能多的(贪婪).

Note the added ?. Now, the capturing group will capture as little as possible (non-greedy), instead of as most as possible (greedy).

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