获取两个字符串之间的内容 PHP [英] Get content between two strings PHP

问题描述

获取两个字符串之间的内容的最佳方法是什么，例如

Whats is the best way to obtain the content between two strings e.g.

ob_start();
include('externalfile.html'); ## see below
$out = ob_get_contents();
ob_end_clean();

preg_match('/{FINDME}(.|
*)+{/FINDME}/',$out,$matches);
$match = $matches[0];

echo $match;

## I have used .|
* as it needs to check for new lines. Is this correct?

## externalfile.html

{FINDME}
Text Here
{/FINDME}

出于某种原因，这似乎在我的代码中的一个地方起作用，而在另一个地方不起作用.我是否以正确的方式解决这个问题?或者有更好的方法吗?

For some reason this appears to work on one place in my code and not another. Am I going about this in the right way? Or is there a better way?

输出缓冲区也是这样做的方式还是file_get_contents?

Also is output buffer the way to do this or file_get_contents?

提前致谢！

推荐答案

• 使用 # 而不是 / 这样您就不必转义它们.
• 修饰符 s 使 . 和 s 也包括换行符.
• { 和 } 具有各种功能，例如 {n,m} 中从 n 到 m 次.

• 基础

  • Use # instead of / so you dont have to escape them.
  • The modifier s makes . and s also include newlines.
  • { and } has various functionality like from n to m times in {n,m}.

  • The basic

    preg_match('#\{FINDME\}(.+)\{/FINDME\}#s',$out,$matches);
    

  • 各种标签等的高级功能(javascript 的样式不太好).

  • The advanced for various tags etc (styling is not so nice by the javascript).

    $delimiter = '#';
    $startTag = '{FINDME}';
    $endTag = '{/FINDME}';
    $regex = $delimiter . preg_quote($startTag, $delimiter) 
                        . '(.*?)' 
                        . preg_quote($endTag, $delimiter) 
                        . $delimiter 
                        . 's';
    preg_match($regex,$out,$matches);
    

  将此代码放入函数中

  • 对于您不想执行任何stray php 代码的任何文件，您应该使用file_get_contents.include/require 甚至不应该是那里的一个选项.
  • For any file which you do not want to execue any stray php code, you should use file_get_contents. include/require should not even be an option there.

  这篇关于获取两个字符串之间的内容 PHP的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！