在字符串为元组的列表中对相同项的值求和 [英] To sum up values of same items in a list of tuples while they are string
本文介绍了在字符串为元组的列表中对相同项的值求和的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
如果我有这样的元组列表:
If I have list of tuples like this:
my_list = [('books', '$5'), ('books', '$10'), ('ink', '$20'), ('paper', '$15'), ('paper', '$20'), ('paper', '$15')]
我如何将列表转到此:
[('books', '$15'), ('ink', '$20'), ('paper', '$50')]
即当两个项目都是元组中的字符串时,添加相同项目的费用.我有价格项目是字符串的问题.任何提示将不胜感激.非常感谢!
i.e. to add the expense of same item while both the items are string in the tuples. I have problem with the price items being string. Any hint would be greatly appreciated. Thanks a lot!
我以这种方式获得第一张清单:
I am getting the first list in this way:
my_list=[]
for line in data:
item, price = line.strip('\n').split(',')
cost = ["{:s}".format(item.strip()), "${:.2f}".format(float(price))]
my_list.append(tuple(cost))
现在my_list
应该看起来像上面给出的那样.
Now my_list
should look like given above.
推荐答案
You can use defaultdict
to do this:
>>> from collections import defaultdict
>>> my_list = [('books', '$5'), ('books', '$10'), ('ink', '$20'), ('paper', '$15'), ('paper', '$20'), ('paper', '$15')]
>>> res = defaultdict(list)
>>> for item, price in my_list:
... res[item].append(int(price.strip('$')))
...
>>> total = [(k, "${}".format(sum(v))) for k, v in res.items()]
>>> total
[('ink', '$20'), ('books', '$15'), ('paper', '$50')]
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