如何根据另一个列表对列表进行排序? Python [英] How to sort a list according to another list? Python

问题描述

所以，如果我有一个列表:

So if I have one list:

name = ['Megan', 'Harriet', 'Henry', 'Beth', 'George']

还有另一个列表，其中每个值以正确的顺序表示名称

And I have another list where each value represents the names in the right order

score_list = [9, 6, 5, 6, 10]

所以，梅根= 9，贝丝= 6(顺便说一句，这是从字典中获得的)

So Megan = 9 and Beth = 6 (this is from a dictionary by the way)

我如何按字母顺序对名称进行排序，但如何使score_list与名称匹配? 我已经使用冒泡排序方法对数字进行了排序，但没有对字符串进行排序.

How would I sort name alphabetically but keep the score_list matching name? I have done the with sorting numbers using the bubble sort method but not strings.

推荐答案

您可以使用zip与元组同时对它们进行排序.排序将按名称进行:

You can sort them at the same time as tuples by using zip. The sorting will be by name:

tuples = sorted(zip(name, score_list))

然后

name, score_list = [t[0] for t in tuples], [t[1] for t in tuples]

这篇关于如何根据另一个列表对列表进行排序? Python的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！