根据另一个列表对元组列表进行排序? [英] Sorting tuple list based on another list?

问题描述

有两个列表.

list1 = [('ST00003', '009830'), ('ST00003', '005490'), ('ST00003', '005830'), ('ST00003', '251270'), ('ST00002', '111710')]
list2 = ['111710', '005830', '009830', '005490', '251270']

我想按list2的顺序对list1进行排序.

I want to sort list1 in order of list2.

list3 = [('ST00002', '111710'), ('ST00003', '005830'), ('ST00003', '009830'), ('ST00003', '005490'), ('ST00003', '251270')]

我想让它在排序时像 list3 一样.有什么好办法吗?

I want to make it like list3 when it's sorted. Is there any good way?

推荐答案

我做了一个中间的 dict ，它从数字字段映射到 list2 中的索引:

I did it my making an intermediate dict which maps from the number field to the index in list2:

list1 = [('ST00003', '009830'), ('ST00003', '005490'), ('ST00003', '005830'), ('ST00003', '251270'), ('ST00002', '111710')]
list2 = ['111710', '005830', '009830', '005490', '251270']

map2 = {value:index for index,value in enumerate(list2)}
print(map2)

list3 = sorted(list1, key = lambda i: map2[i[1]])
print(list3)

根据需要输出.

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