更改子列表中的字符 [英] Change Character in Sublist
本文介绍了更改子列表中的字符的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我已经知道这是一个非常愚蠢的问题.我试图查找答案,但我几乎不知道该问些什么. (抱歉,标题有点模糊).但是,我走了.我有一个词表.我想摆脱该列表中的不良字符.
I already know this is a really dumb question. I tried looking up my answer but I barely know what to ask. (sorry if the title is a little vague). But Here I go. I have a list of words. I'm wanting to get rid of the bad characters in that list.
List = ["I?", "Can", "!Not", "Do.", "It"]
BadChars = ["?", "!", "."]
for word in List:
for char in word:
if char in BadChars:
char = ""
print(List)
同样,我知道这很简单,但是我无法弄清楚.原谅我.
Again, I know this is very simple, but I just can't figure it out. Forgive me.
顺便说一句,这没有给我一个错误.只是返回了未更改的列表.
Btw, it's not giving me an error. It's just returning the List untouched.
推荐答案
对于每个单词的每个字符,您可以使用replace
方法:
You could use the replace
method, for each char for each word:
List = ["I?", "Can", "!Not", "Do.", "It"]
BadChars = ["?", "!", "."]
for i in range(len(List)):
for char in BadChars:
List[i] = List[i].replace(char, "")
print(List) # ==> ['I', 'Can', 'Not', 'Do', 'It']
也可以使用正则表达式:
A regex may be used as well:
import re
List = ["I?", "Can", "!Not", "Do.", "It"]
BadChars = ["?", "!", "."]
rgx = '[%s]'%(''.join(BadChars))
List = [re.sub(rgx, "", word) for word in List]
print(List) # ==> ['I', 'Can', 'Not', 'Do', 'It']
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