在元组的python列表中查找最大值 [英] finding maximum value in python list of tuples

问题描述

我有一个元组列表(列表):

I have a list of tuples (list):

('2015-06-19', 3453455, 5, 'Scheduled')
('2015-05-19', 6786788, 6, 'Overdue')
('2015-04-19', 2342344, 2, 'Not Received')
('2015-03-19', 9438549, 0, 'Not Received')
('2015-02-19', 6348759, 7, 'Not Received')

当我运行它时，我得到了:

When I run this, I get this:

>>> print(max(list))
('2015-06-19', 3453455, 5, 'Scheduled')

很明显，max(list)根据元组列表中的第一个值确定最大值.我只是想知道这是否是关于元组列表的max(list)的默认行为；只检查元组中的第一项?

Obviously, max(list) determined the max based on the first value in the list of tuples. I'm just wondering if this is the default behavior of max(list) in regards to a list of tuples; to check only the first item in the tuple?

然后，如果我想返回基于第二个项目/列的最大值的元组，该怎么办?我该怎么办?

And, what if I wanted to return the tuple with the maximum based on the second item/column. How would I do that?

推荐答案

您可以指定使用lambda进行比较的字段

You can specify which field to use for comparison using lambdas

max(list,key=lambda x:x[1])

或使用itemgetter

from operator import itemgetter
max(list,key=itemgetter(1))

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