获取元组列表中的最大值 [英] Get the max value on a list of tuples

问题描述

我有一个元组列表:

card_list= [(2, (1, S)), (0, (12, H)), (1, (5, C)]

此列表包含卡片:(cardindex，(value，suit))，其中cardindex是存储卡片位置的索引，但与我的特定问题无关.

This list contains cards: (cardindex, (value, suit)) where cardindex is a index to store the position of the card but irrelevant for this my particular question.

因此，在示例中，列表中有3张卡片:

So in the example there are 3 cards in the list:

• (2，(1，S))=索引为2的黑桃王牌.
• (0，(12，H))=国王索引为0的Hearts
• (1，(5，C))= 5个索引为1的俱乐部

好吧，我的问题是:我希望获得具有最大值的物品，这就是我必须获得的物品:(0，(12，H))

Well, my question is: I desire to obtain the item with the max value, this is, i have to get the item: (0, (12, H))

我的尝试是:

CardWithHighestValue= max(card_list,key=itemgetter(1)[0])

但是我得到了物品或价值?最重要的是:那句话真的正确吗?

But I get the item or the value? And the most important: is it really correct that sentence?

谢谢.

推荐答案

替换

CardWithHighestValue= max(card_list,key=itemgetter(1)[0])

使用

CardWithHighestValue= max(card_list,key=itemgetter(1))

演示

from operator import itemgetter
card_list= [(2, (1, "S")), (0, (12, "H")), (1, (5, "C"))]
print max(card_list,key=itemgetter(1)) 

card_list= [(2, (1, "S")), (0, (4, "H")), (1, (5, "C"))]
print max(card_list,key=itemgetter(1))

输出:

(0, (12, 'H'))
(1, (5, 'C'))

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