从列表中删除偶数 [英] remove even numbers from a list

问题描述

如何从列表中删除偶数?

How can I remove even numbers from a list?

a = []
i = 0


while i < 10:
    c = int(raw_input('Enter an integer: '))
    a.append(c)
    i += 1  # this is the same as i = i + 1
    for i in a:
        if i % 2 == 0:
            a.remove(i)
print(a)

即使输入10个数字，它也会一直要求输入数字

This keeps asking for numbers even after 10 have been entered

推荐答案

如果数字为偶数，为什么不阻止附加，而不是添加然后检查是否删除?

Why not preventing the append if the number is even, instead of adding and then checking for removal?

a = []
counter = 0
while counter < 10:
    c = int(raw_input('Enter an integer: ')) 
    if c % 2 != 0:
        a.append(c)
    counter += 1
print(a)

这篇关于从列表中删除偶数的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！